12 Nov
2013
12 Nov
'13
12:41 p.m.
On Tue, Nov 12, 2013 at 12:33 PM, Patrik D'haeseleer <patrikd(a)gmail.com>wrote;wrote:
The figure
<http://www.jneurosci.org/content/21/16/6405/F5.expansion.html>I
linked to earlier suggests the 50% drop-off should be around 420-520nm,
which covers pretty much all of the blue range of the spectrum.
This is another reason I'd like to play around with subtracting the red
signal. Depending on what the spectral response curves are, it might be
possible to play around with multipliers and get close to the shape of the
graph. (Granted, that it might also turn out to just including the blue
signal, but I really need to *know* what that is, not make an educated
guess about it.)
The photodiode you listed seems pretty much a perfect
match. No need to
muck around with narrow band-pass filters.
For the purpose of the intended distribution context and audience, I should
**avoid** requiring other to be mucking around with photodiodes. The fact
that a photodiode detector's curve matches another really doesn't change
that.